SOLUTION: 25(x+5)^2 + 4(y-3)^2 = 100 axis to which the major axis is parallel and the center. I think it may be x and -5, 3 but i am not sure if i did this correctly i would appreciat

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: 25(x+5)^2 + 4(y-3)^2 = 100 axis to which the major axis is parallel and the center. I think it may be x and -5, 3 but i am not sure if i did this correctly i would appreciat      Log On


   



Question 324548: 25(x+5)^2 + 4(y-3)^2 = 100
axis to which the major axis is parallel and the center.
I think it may be
x and -5, 3
but i am not sure if i did this correctly
i would appreciate your help

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
25(x+5)^2 + 4(y-3)^2 = 100
Divide thru by 100 to get:
(x+5)^2/4 + (y-3)^2/25 = 1
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The center is (-5,3)
But the major axis has length 2a = 10
and is parallel to the y-axis.
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Plot the vertices and you will see that.
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Cheers,
Stan H.
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axis to which the major axis is parallel and the center.
I think it may be
x and -5, 3