SOLUTION: how do you write in standard form y = 1/3(x-2)^2 + 4? I know how to do some of the problem. I'm stuck on how to get rid of the 1/3.
y = 1/3(x-2)^2 + 4
y = 1/3(x^2 - 4x + 4)
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-> SOLUTION: how do you write in standard form y = 1/3(x-2)^2 + 4? I know how to do some of the problem. I'm stuck on how to get rid of the 1/3.
y = 1/3(x-2)^2 + 4
y = 1/3(x^2 - 4x + 4)
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Question 312030: how do you write in standard form y = 1/3(x-2)^2 + 4? I know how to do some of the problem. I'm stuck on how to get rid of the 1/3.
y = 1/3(x-2)^2 + 4
y = 1/3(x^2 - 4x + 4) + 4
y = (x^2)/3 - 4x/3 + 4/3 + 4 or 3y = x^2 - 4x + 8
This is where I am stuck....help please!!!!!! Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Why don't you multiply by 3 first, expand and then divide by 3 at the end if the (1/3) is giving you problems?
The first expression in your last line is correct, just work out ().
