SOLUTION: put the following equation in standard form, identify center and radius and graph. x squared + y squared+ 6x-4y+12=0

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: put the following equation in standard form, identify center and radius and graph. x squared + y squared+ 6x-4y+12=0      Log On


   

Question 298080: put the following equation in standard form, identify center and radius and graph. x squared + y squared+ 6x-4y+12=0
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + y^2+ 6x-4y+12=0


x^2+6x+9-9 + y^2-4y+4-4+12=0

(x+3)^2-9 + (y-2)^2-4+12=0


(x+3)^2+(y-2)^2=1

Circle with center (-3,2) and radius 1