SOLUTION: Find the Exact solution(s) of each system of equalities. y = x - 2 y = x (squared) - 2

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Question 292745: Find the Exact solution(s) of each system of equalities.
y = x - 2
y = x (squared) - 2
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
y = x - 2
y = x (squared) - 2
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x%5E2+-+2+=+x+-+2
x%5E2+=+x
x = 0, y = -2
x = 1, y = -1
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The answers are obvious.
If not:
x%5E2+=+x
x%5E2+-+x+=+0
x*(x-1) = 0
x = 0
x = 1