SOLUTION: Write the equation of the tangent line. Please put your answer in the form y=mx+b. The equation of a circle and a point on the circle is
given. x^2+y^2=5; (2, 1)
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-> SOLUTION: Write the equation of the tangent line. Please put your answer in the form y=mx+b. The equation of a circle and a point on the circle is
given. x^2+y^2=5; (2, 1)
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Question 286922: Write the equation of the tangent line. Please put your answer in the form y=mx+b. The equation of a circle and a point on the circle is
given. x^2+y^2=5; (2, 1) Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! You need to find the center of the circle.
find the line from the center of the circle through the given point .
find the slope.
get the negative reciprocal (new slope ) of that (old)slope
that is find the number (new slope) whose product with slope which will get -1
then find a line through (2,1) with that (new) slope
