SOLUTION: what is the equation for the conic section? it is an ellipse with the vertices (-2,4) and (-2,-6). covertices are (-4,-1) and (0,-1). and what are the foci?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: what is the equation for the conic section? it is an ellipse with the vertices (-2,4) and (-2,-6). covertices are (-4,-1) and (0,-1). and what are the foci?      Log On


   



Question 284081: what is the equation for the conic section? it is an ellipse with the vertices
(-2,4) and (-2,-6). covertices are (-4,-1) and (0,-1). and what are the foci?

Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
what is the equation for the conic section? it is an ellipse with the vertices
(-2,4) and (-2,-6). covertices are (-4,-1) and (0,-1). and what are the foci?


what is the equation for the conic section? it is an ellipse with the vertices
(-2,4) and (-2,-6). covertices are (-4,-1) and (0,-1). and what are the foci? 


Plot those 4 points:
 

 
Connect them to show the major and minor axes
of the ellipse:
 

 
Sketch in the ellipse:
 


Since the ellipse has its major axis vertical,
it has the standard form:
 
%28x-h%29%5E2%2Fb%5E2+%2B+%28y-k%29%5E2%2Fa%5E2+=+1
 
where 
 
1. (h,k) = the center 
 
2. a = the distance from the center to either of the two vertices
 
3. b = the distance from the center to either of the the covertices.
 
We can see from the graph that 
 
1. the center of the ellipse is (h,k) = (-2,-1)
 
2. a = 5
 
3. b = 2
 
So the equation 
 
%28x-h%29%5E2%2Fb%5E2+%2B+%28y-k%29%5E2%2Fa%5E2+=+1
 
becomes
 
%28x-%28-2%29%29%5E2%2F2%5E2+%2B+%28y-%28-1%29%29%5E2%2F5%5E2+=+1
 
or
 
%28x%2B2%29%5E2%2F4+%2B+%28y%2B1%29%5E2%2F25+=+1

to find the foci, we calculate c by
this Pythagorean relation:

c%5E2=a%5E2-b%5E2

c%5E2=5%5E2-2%5E2

c%5E2=25-4

c%5E2=21

c=sqrt%2821%29

The two foci are on the major axis c usits
from the center, so they are

(-2,-1+sqrt%2821%29) and (-2,-1-sqrt%2821%29)

 
Edwin