SOLUTION: I'm not sure how to solve quadratic systems. Here is an example of a problem: {{{(x-2)^2+y^2=5}}} x-y=1

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Question 270001: I'm not sure how to solve quadratic systems. Here is an example of a problem:
%28x-2%29%5E2%2By%5E2=5
x-y=1
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I'm not sure how to solve quadratic systems. Here is an example of a problem:
(x-2)^2+y^2=5
x-y=1
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Solve the linear equation for "x" and solve for "y":
---
x = y+1
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(y+1-2)^2 + y^2 = 5
----
(y-1)^2 + y^2 = 5
y^2 - 2y + 1 + y^2 = 5
2y^2 - 2y -4 = 0
2(y^2 - y -2) = 0
Factor:
2(y-2)(y+1) = 0
y = 2 or y = -1
------------------------
Solve for "x"
Since x = y+1, if y=2 then x = 3
Since x = y+1, if y = -1 then x = 0
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Solutions:
(3,2) and (0,-1)
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Cheers,
Stan H.