SOLUTION: find all(x,y) that satisfy x²+3y²= 52 and x²= 3y+16.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find all(x,y) that satisfy x²+3y²= 52 and x²= 3y+16.      Log On


   

Question 249220: find all(x,y) that satisfy x²+3y²= 52 and x²= 3y+16.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Sub for x^2 into 1st eqn
3y%2B16+%2B+3y%5E2+=+52
3y%5E2+%2B+3y+-+36+=+0
y%5E2+%2B+y+-+12+=+0
(y+4)*(y-3) = 0
y = -4
y = 3
-----
y = -4, x = ±2
y = 3, x = ±5