SOLUTION: Please help me solve this equation: {{{ (x-2)^2=4y) }}}. I can not find the vertex, focus, or the directrix.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Please help me solve this equation: {{{ (x-2)^2=4y) }}}. I can not find the vertex, focus, or the directrix.      Log On


   

Question 22463: Please help me solve this equation: +%28x-2%29%5E2=4y%29+. I can not find the vertex, focus, or the directrix.
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
(X-2)^2=Y
THIS IS OF THE FORM (X-H)^2=4A(Y-K)..WHERE
H=2,K=0,A=1/4,.....
..HENCE THIS IS A PARABOLA WITH
FOCUS AS (H,K+A)..THAT IS (2,1/4)
VERTEX AS (H,K)...THAT IS (2,0)
AXIS AS X-H=0...THAT IS X-2=0
AND
DIRECTRIX AS Y-K+A=0...THAT IS Y+1/4=0