SOLUTION: is the problem: 3x2+3y2-4y-8+=0 (the 2 means squared) A) circle B) ellipse C) hyperbola D) parabola ???

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: is the problem: 3x2+3y2-4y-8+=0 (the 2 means squared) A) circle B) ellipse C) hyperbola D) parabola ???      Log On


   

Question 197359: is the problem: 3x2+3y2-4y-8+=0 (the 2 means squared)
A) circle B) ellipse C) hyperbola D) parabola
???
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


There is an term AND a term, so it is NOT a parabola.

The signs on the and terms are the same, so it is NOT a hyperbola.

The coefficients on the and terms are equal, so it is NOT an ellipse; it is a circle.

Specifically, a circle centered at with radius

John