SOLUTION: how do you find the points of intersection for x^2 + y^2=25 x + y^2=5
Algebra
->
Quadratic-relations-and-conic-sections
-> SOLUTION: how do you find the points of intersection for x^2 + y^2=25 x + y^2=5
Log On
Algebra: Conic sections - ellipse, parabola, hyperbola
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Quadratic-relations-and-conic-sections
Question 185557
:
how do you find the points of intersection for
x^2 + y^2=25
x + y^2=5
Answer by
edjones(8007)
(
Show Source
):
You can
put this solution on YOUR website!
x^2 + y^2=25
x + y^2=5
.
x=5-y^2
(5-y^2)^2+y^2=25 substitute 5-y^2 for x.
y^4-10y^2+25+y^2=25
y^4-9y^2=0
y^2(y^2-9)=0
y^2(y+3)(y-3)=0
y=0, x=5; y=3, x=-4; y=-3 x=4
.
Ed
.