SOLUTION: Given the Parabola: x^2+2y+2=0 A. find the vertex B. find the focus C. Find the directrix D. graph the function THANKS!

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Given the Parabola: x^2+2y+2=0 A. find the vertex B. find the focus C. Find the directrix D. graph the function THANKS!      Log On


   



Question 181825: Given the Parabola: x^2+2y+2=0
A. find the vertex
B. find the focus
C. Find the directrix
D. graph the function
THANKS!

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
Given the Parabola: x^2+2y+2=0
A. find the vertex
B. find the focus
C. Find the directrix
D. graph the function
:
x%5E2%2B2y%2B2=0
:
x%5E2=-2%28y%2B1%29
:
vertex is at (0,-1) (h,k)
:
4p=-2-->p=-1/2
:
to get focus coordinates-subtract p from k( the vertex's y coordinate) to find the focus's y coordinate.....the x coordinate is h(the vertex's x coordinate)
:
directrix for vertical parabola is y=k-p
:
focus(0,-1-1/2)-->(0,-3/2)
:
directrix(y=-1+1/2)--->y=-1/2
:
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28-1%2F2%29x%5E2-1%29