SOLUTION: The vertex of the parabola below is at the point (1, 3) and the point (2, 6) is on the parabola. What is the equation of the parabola? i had gotten y = 6(x - 1)^2 + 3 but it cam

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: The vertex of the parabola below is at the point (1, 3) and the point (2, 6) is on the parabola. What is the equation of the parabola? i had gotten y = 6(x - 1)^2 + 3 but it cam      Log On


   

Question 144994: The vertex of the parabola below is at the point (1, 3) and the point (2, 6) is on the parabola. What is the equation of the parabola?
i had gotten y = 6(x - 1)^2 + 3 but it came out wrong.
these are the other options
A. y = 3(x + 1)^2 - 3
C. y = 3(x - 1)^2 + 3
D. x = 2(y - 3)^2 + 1


Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Since the vertex is (1,3) this means y=a%28x-1%29%5E2%2B3


6=a%282-1%29%5E2%2B3 Now plug in x=2 and y=6


6=a%281%29%5E2%2B3 Subtract


6=a%281%29%2B3 Square 1 to get 1


6=a%2B3 Multiply


3=a Subtract 3 from both sides


So the equation is y=3%28x-1%29%5E2%2B3 which means that the answer is choice C)

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The vertex of the parabola below is at the point (1, 3) and the point (2, 6) is on the parabola. What is the equation of the parabola?
i had gotten y = 6(x - 1)^2 + 3 but it came out wrong.
these are the other options
A. y = 3(x + 1)^2 - 3
C. y = 3(x - 1)^2 + 3
D. x = 2(y - 3)^2 + 1
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Form:
y = a(x-h)^2 + k
6 = a(2-1)^2 + 3
6 = a+3
a = 3
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EQUATION:
y = 3(x-1)^2+3
Answer: C
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Cheers,
Stan H.