SOLUTION: What is the x-coordinate of the center of the ellipse with the following equation? (y+6)^2/18+(x-5)^2/4=5

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What is the x-coordinate of the center of the ellipse with the following equation? (y+6)^2/18+(x-5)^2/4=5       Log On


   

Question 144993: What is the x-coordinate of the center of the ellipse with the following equation?
(y+6)^2/18+(x-5)^2/4=5
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28y%2B6%29%5E2%2F18%2B%28x-5%29%5E2%2F4=5 Start with the given equation


%28x-5%29%5E2%2F4%2B%28y%2B6%29%5E2%2F18=5 Rearrange the terms


%28x-5%29%5E2%2F20%2B%28y%2B6%29%5E2%2F90=1 Divide both sides by 5



So the equation is in the form %28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1 where h=5, k=-6, a=2%2Asqrt%285%29, and b=3%2Asqrt%2810%29


Since the x-coordinate of the center is x=h this means that the x-coordinate of the center is x=5

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
5
Cheers,
Stan H.