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Question 135906: how would I graph y2=12x (is this a parabola?)
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! how would I graph y^2=12x (is this a parabola?)
It is a parabola opening to the right.
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Solve for "x":
x = (1/12)y^2
If y = 0, x=0
If y = +sqrt(12), x = 1
If y = -sqrt(12), x = 1
So the vertex is at (0,0)
The other two points are symmetric to the x-axis and to the right.
Continue the graph as a parabola opening to the right.
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cheers,
stan H.
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