Question 134982: following equation defines a relation (x,y). Write the domain and range of each relation.
x^2/9 + y^2/16 = 1 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Write the domain and range of each relation.
x^2/9 + y^2/16 = 1
(y^2/16) = 1 - (x^2/9)
y^2 = 16[1-(x^2/9)]
y = +-4sqrt[1-(x^2/9)]
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Domain: All Real Numbers between -3 and 3
Range: All Real Numbers between -4 and 4
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