SOLUTION: How would I find the focus and the directrix for the parabola y=1/12 x to the second power? Please help! Thank You!

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: How would I find the focus and the directrix for the parabola y=1/12 x to the second power? Please help! Thank You!       Log On


   



Question 128667: How would I find the focus and the directrix for the parabola y=1/12 x to the second power? Please help! Thank You!


Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
YOU FIND THE FOCI & THE DIRECTRIC BY PLOTTING THE EQUATION THUS:
Y=(X^2/12)
+graph%28+300%2C+200%2C+-16%2C+15%2C+-10%2C+10%2C+x%5E2%2F12+%29 (graph 300x200 pixels, x from -16 to 15, y from -10 to 10, x^2/12).