SOLUTION: Find an equation for a parabola with vertex (-3,2) and focus (2,2)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find an equation for a parabola with vertex (-3,2) and focus (2,2)      Log On


   



Question 1204078: Find an equation for a parabola with vertex (-3,2) and focus (2,2)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
First, plot the vertex and the focus to understand the orientation of the parabola.
In this case, we have a parabola that opens to the right. The form of the equation for this type of parabola is:
4p%28x-h%29=%28y-k%29%5E2

where the vertex is at ( h , k ) and +p+ is the distance from the vertex to the focus.
For the given problem, we have vertex (-3 ,2 ) and focus (2 ,2 )
( h , k )=(-3 ,2 ) and the distance from the vertex to the focus p=5
. Therefore, the required equation is:
4%2A5%28x-%28-3%29%29=%28y-2%29%5E2
20%28x%2B3%29=%28y-2%29%5E2