SOLUTION: The parametric equation of a curve is 𝑥 = h + 𝑎 sec 𝑡 , 𝑦 = 𝑘 + 𝑏 csc 𝑡. By eliminating the parameter t, it can be demonstrated that the curve is A) a circle

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: The parametric equation of a curve is 𝑥 = h + 𝑎 sec 𝑡 , 𝑦 = 𝑘 + 𝑏 csc 𝑡. By eliminating the parameter t, it can be demonstrated that the curve is A) a circle       Log On


   

Question 1199622: The parametric equation of a curve is 𝑥 = h + 𝑎 sec 𝑡 , 𝑦 = 𝑘 + 𝑏 csc 𝑡. By eliminating the parameter t, it can be demonstrated that the curve is
A) a circle B) an ellipse C) a parabola D) a hyperbola E) a cycloid
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
 



That's the conic section equation you get when 
eliminating the parameter t.  However there is
no way to answer your question, because we have 
no information given about the values of a and b.

If a=-b, a≠0, the answer is A)
If a=0 and b≠0 or a≠0 and b=0, the answer is C)
If a and b have the same sign, the answer is D)
If a and b have opposite signs, the answer is B)

Edwin