SOLUTION: A tunnel in parabolic shape is defined by the x^2-16y=0 (dimensions measured in feet). What is its width at the base?

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Question 1196512: A tunnel in parabolic shape is defined by the x^2-16y=0 (dimensions measured in feet). What is its width at the base?
Found 3 solutions by Alan3354, ikleyn, math_tutor2020:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A tunnel in parabolic shape is defined by the x^2-16y=0 (dimensions measured in feet). What is its width at the base?
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There's no base.

Answer by ikleyn(52802) About Me  (Show Source):
You can put this solution on YOUR website!
.
A tunnel in parabolic shape is defined by the x^2-16y=0 (dimensions measured in feet). What is its width at the base?
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In  Math,  if the opposite is not pointed explicitly,  y-axis in a coordinate plane,  by default,  is directed vertically up.

In accordance with this conception,  your parabolic tunnel is upside down.


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Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

As the other tutors have pointed out, the parabola opens upward, which means the tunnel archway is upside down.

Here's the graph:
https://www.desmos.com/calculator/u0db7reprz
You'll need to let your teacher know about the typo.