SOLUTION: Determine the domain of y= f(x) = cos^-1(3x + 2) and solve the equation y = 𝜋/4

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Question 1195187: Determine the domain of y= f(x) = cos^-1(3x + 2) and solve the equation y = 𝜋/4
Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

Part 1: Finding the domain.

Recall that the smallest cosine can get is -1, and the largest is 1
I.e. the outputs are between -1 and 1, inclusive of both endpoints

This tells us the range is
-1+%3C=+cos%28x%29+%3C=+1

This then leads directly to the fact that the domain of is -1+%3C=+x+%3C=+1.
The domain and range swap places when going from the original to the inverse function.
This swap is because x and y themselves swap roles.

Therefore, the input expression 3x+2 must be between -1 and 1
-1+%3C=+3x%2B2+%3C=+1

-1-2+%3C=+3x%2B2-2+%3C=+1-2 Subtracting 2 from all sides

-3+%3C=+3x+%3C=+-1

-3%2F3+%3C=+3x%2F3+%3C=+-1%2F3 Dividing all sides by 3

-1+%3C=+x+%3C=+-1%2F3
The inequality signs stay the same the entire time. They only would flip if we divided all sides by a negative number.

Answer: The domain as a compound inequality is -1+%3C=+x+%3C=+-1%2F3
Verbally we can say x must be between -1 and -1/3, inclusive of both endpoints.
In interval notation, the domain is [-1, -1/3]. Don't forget the square brackets.

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Part 2: Solve the equation for x when y = pi/4