SOLUTION: Write the equation of the circle centered at (−7,−2) that passes through (13,−15).

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Question 1187847: Write the equation of the circle centered at (−7,−2) that passes through (13,−15).

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Distance between those two given points is radius.
cross%28%28-7-13%29%5E2%2B%28-2-%28-5%29%29%5E2%29
%28-7-13%29%5E2%2B%28-2-%28-15%29%29%5E2
SQUARE of the radius is 569 .

%28x%2B7%29%5E2%2B%28y%2B2%29%5E2=569

Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
.
Write the equation of the circle centered at (−7,−2) that passes through (13,−15).
~~~~~~~~~~~~~~~~~~ 


The distance between the points is


    sqrt%28%2813-%28-7%29%29%5E2+%2B+%28%28-15%29-%28-2%29%29%5E2%29 = sqrt%2820%5E2+%2B+13%5E2%29 = sqrt%28569%29.


Therefore, the equation of the circle in standard form is


    %28x-%28-7%29%29%5E2 + %28y-%28-2%29%29%5E2 = 569

or

    %28x%2B7%29 + %28y%2B2%29%5E2 = 569.

Solved.

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The equation in the post by @josgarithmetic is INCORRECT.

For your safety, ignore his post.