SOLUTION: Write the equation of the hyperbola. Co - Ve Vertices: (1, 5) , (1, 1) Focus : (4, 3)

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Question 1187217: Write the equation of the hyperbola. Co - Ve Vertices: (1, 5) , (1, 1) Focus : (4, 3)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
the equation of the hyperbola:
%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1
the length of the transverse axis is +2a
the coordinates of the vertices are (h ± a, k)
the length of the conjugate axis is 2b
the coordinates of the co-vertices are (h , k ±+b )
the distance between the foci is 2c, where c%5E2=a%5E2%2Bb%5E2
the coordinates of the foci are (h ±c, k)
given:
Co -Vertices: (1, 5) , (1, 1)
we know that the center is half way between: (%281%2B1%29%2F2,%285%2B1%29%2F2)=(1,3) => so, +h=1 and +k=3

use Co -Vertices: (1, 5), +h=1 and +k=3 to find b
(1 , 3±b )=(1, 5)
(1 , 3±b )=(1, 5)=>3±b=5 =>±b=2

the coordinates of the foci are (h+±c, k)= (4,+3) =>(1 ±c,+3)= (4, 3) =>1 ±c=4=>±c=4-1=>±c=3

then c%5E2=a%5E2%2Bb%5E2=>3%5E2=a%5E2%2B2%5E2=>a%5E2=9-4=5

and your equation is:
%28x-1%29%5E2%2F5-%28y-3%29%5E2%2F4=1