SOLUTION: What are the foci of the hyperbola with the equation y²/12-x²/5 = 1

From the given equation of the hyperbola, you have these two equations for its semi-axis "a"  and  "b"


    a^2 = 12;  b^2 = 5.


The hyperbola is open vertically up and down.  The transverse axis is vertical y-axis; the imaginary axis is horizontal x-axis.


Vertical semi-axis (transverse) is  a = .


The vertices of the hyperbola are the point  (,)  and  (,)  on y-axis.



For the half the distance "c" between the foci we have this equation


    c =  =  =  = 4.1231 (rounded).


The foci are these points  F1 = (,)  and  (,)  on y-axis.