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Question 1176570: State the focus of Parabola where the equation in y=-16x^2
a) 4
b) 16
c) -8
d) -4
Found 3 solutions by greenestamps, MathLover1, Solver92311: Answer by greenestamps(13200) (Show Source):
You can put this solution on YOUR website!
This is an example of a problem that is conceived extremely poorly.
The statement of the problem is sloppy: "...focus of Parabola..." "Parabola" with a capital p? and "focus of Parabola" instead of "focus of the parabola"?
And none of the answer choices makes sense; they are all single values, whereas the focus is an ordered pair of x and y values. Given the equation y=-16x^2, the vertex is at the origin, so we can assume the answer choices are supposed to be (0,4), (0,16), (0,-8), and (0,-4) instead of just 4, 16, -8, and -4.
Getting past the poor presentation of the problem, let's see what we find when we try to solve it.
The vertex form of the equation of a parabola is

where the vertex is (h,k) and p is the directed distance from the directrix to the vertex, and from the vertex to the focus.
In this problem, the vertex is at (0,0), so the equation is

Since the coefficient of x^2 is -16, we have



With the vertex at (0,0 and p=-1/64, the focus is at (0,-1/64) -- not anywhere close to any of the answer choices.
Answer by MathLover1(20850) (Show Source): Answer by Solver92311(821) (Show Source):
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