SOLUTION: Find the equation of the ellipse if the endpoints of minor axis are (1,3) and (1,-1) with a focus at (-1,1).Express your answer in general form.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the equation of the ellipse if the endpoints of minor axis are (1,3) and (1,-1) with a focus at (-1,1).Express your answer in general form.       Log On


   



Question 1168920: Find the equation of the ellipse if the endpoints of minor axis are (1,3) and (1,-1) with a focus at (-1,1).Express your answer in general form.


Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!


The equation of an ellipse can be given as,
%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1
where
'a' represents the semi-major axis (half of the length of the major axis)
'b' represents the semi-minor axis (half of the length of the minor axis)
h’ represents the x+coordinate of the center
k’ represents the y coordinate of the center

if the endpoints of minor axis are (1,3) and (1,-1) , minor axis length is equal to the distance between them which is 4
half of the length of the minor axis is b=4%2F2=2
=> the center mast be half way between endpoints, and it is at (1,1)

a focus at (-1,1)

the distance between foci (-1,1) and center (1,1)
focus is 2+units from the center, so c+=+2

using the Pythagorean fact of all ellipses
a%5E2=c%5E2%2Bb%5E2
a%5E2=2%5E2%2B2%5E2=8

so, your formula is
%28x-1%29%5E2%2F8%2B%28y-1%29%5E2%2F4=1