SOLUTION: Find an equation in standard form of the parabola described. Vertex at (−2, 4); passes through (0, −4) Form: (y-k)*2=4p(x-h)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find an equation in standard form of the parabola described. Vertex at (−2, 4); passes through (0, −4) Form: (y-k)*2=4p(x-h)      Log On


   

Question 1162553: Find an equation in standard form of the parabola described.
Vertex at (−2, 4); passes through (0, −4)
Form: (y-k)*2=4p(x-h)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!


standard form:
%28y-k%29%5E2+=4p%28x-h%29 where h and k are coordinates of vertex
since given vertex at (-2, 4), we have
%28y-4%29%5E2+=4p%28x-%28-2%29%29
%28y-4%29%5E2+=4p%28x%2B2%29 .........eq.1

since passes through (0,+-4), we have
%28y-4%29%5E2+=4p%28x%2B2%29
%28-4-4%29%5E2+=4p%280%2B2%29
64=8p
p=64%2F8
p=8
so, your equation is:
%28y-4%29%5E2+=4%2A8%28x%2B2%29
%28y-4%29%5E2+=32%28x%2B2%29