SOLUTION: Find the equation of a line normal to the curve x^2=16y at (4,1).

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Question 1161791: Find the equation of a line normal to the curve x^2=16y at (4,1).
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Rewrite the given equation so that y is a function of x.

Take the first derivative of the function and evaluate at x = 4 giving you the slope of the tangent line at (4,1)

Use the negative reciprocal of the slope of the tangent line and the point (4,1) in the Point-Slope form to write an equation for the line normal to the given curve at the given point. You cannot write the equation for a line because there is a myriad of forms for the equation of any given line.


John

My calculator said it, I believe it, that settles it