SOLUTION: Find the standard form of the equation for a hyperbola with the vertices (5,0) and (-5,0) and that passes through (6,11) I don't know how to plug in the a, x and y values in ord

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the standard form of the equation for a hyperbola with the vertices (5,0) and (-5,0) and that passes through (6,11) I don't know how to plug in the a, x and y values in ord      Log On


   

Question 1153601: Find the standard form of the equation for a hyperbola with the vertices (5,0) and (-5,0) and that passes through (6,11)
I don't know how to plug in the a, x and y values in order to get the right answer - thanks
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Given vertices at (-5,0) and (5,0), the standard form of the equation is

x%5E2%2F5%5E2+-+y%5E2%2Fb%5E2+=+1

Plug in the coordinates of the other given point to determine b^2 to finish the problem.

6%5E2%2F5%5E2+-+11%5E2%2Fb%5E2+=+1
36%2F25+-+121%2Fb%5E2+=+1
121%2Fb%5E2+=+36%2F25-1+=+11%2F25
b%5E2+=+275

The equation is

x%5E2%2F25+-+y%5E2%2F275+=+1

A graph....