SOLUTION: Find the standard form of the equation of the hyperbola satisfying the given conditions. ​x-intercepts (0,24) and (0,-24). foci at (-25,0) and (25,0) The equation in standard

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the standard form of the equation of the hyperbola satisfying the given conditions. ​x-intercepts (0,24) and (0,-24). foci at (-25,0) and (25,0) The equation in standard      Log On


   



Question 1150044: Find the standard form of the equation of the hyperbola satisfying the given conditions.
​x-intercepts (0,24) and (0,-24). foci at (-25,0) and (25,0)
The equation in standard form of the hyperbola is..

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


(0,24) and (0,-24) are y-intercepts, not x-intercepts.

I will assume you mean (-24,0) and (24,0).

The major axis is horizontal, and the center is at (0,0), so the equation in standard form is

x%5E2%2Fa%5E2-y%5E2%2Fb%5E2=1

a is the distance from the center of the hyperbola to each vertex (half the length of the transverse axis), which is 24.

b is half the length of the conjugate axis, which is not given.

a and b are related by the equation

a%5E2%2Bb%5E2=c%5E2

where c is the distance from the center of the hyperbola to each focus, which is 25.

So

24%5E2%2Bb%5E2+=+25%5E2
576%2Bb%5E2+=+625
b%5E2+=+49

The equation of the hyperbola is

x%5E2%2F576+-+y%5E2%2F49+=+1