SOLUTION: The graph of x^2+y^2+6x-24y+72=0 & x^2-y^2+6x+16y-46=0 intersect at four points. Compute the sum of distance from these four points from the point (-3,2).

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: The graph of x^2+y^2+6x-24y+72=0 & x^2-y^2+6x+16y-46=0 intersect at four points. Compute the sum of distance from these four points from the point (-3,2).      Log On


   

Question 1144475: The graph of x^2+y^2+6x-24y+72=0 & x^2-y^2+6x+16y-46=0 intersect at four points. Compute the sum of distance from these four points from the point (-3,2).
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The graph of x^2+y^2+6x-24y+72=0 & x^2-y^2+6x+16y-46=0 intersect at four points. Compute the sum of distance from these four points from the point (-3,2).
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Find the 4 points, then find the 4 distances, then add them.
There might be some algorithm or method for this, but I don't know of one.