SOLUTION: Determine the standard form of the equation of the ellipse with center at (-4,7), a focus at (-4,11), and a vertex at (-4,12).

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Determine the standard form of the equation of the ellipse with center at (-4,7), a focus at (-4,11), and a vertex at (-4,12).      Log On


   



Question 1144229: Determine the standard form of the equation of the ellipse with center at (-4,7), a focus at (-4,11), and a vertex at (-4,12).
Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!

That is an ellipse with a vertical major axis, so it looks like the
number zero 0, and has this standard equation:
%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1
where
(h,k) = center = (-4,7)
a = distance from center to vertex = 5 units
c = distance from center to focus = 4 units.
b = distance from center to covertex, found by c²=a²-b²
4²=5²-b²
16=25-b²
b²=25-16
b²=9
b=3

%28x-%28-4%29%29%5E2%2F3%5E2%2B%28y-%287%29%29%5E2%2F4%5E2=1
%28x%2B4%29%5E2%2F9%2B%28y-7%29%5E2%2F25=1
Edwin