SOLUTION: write the equation of the hyperbola in standard form given the corners of refrence rectangle (19,15),(19,-1),(-15,-1),(-15,15) and horizontal transverse axis.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: write the equation of the hyperbola in standard form given the corners of refrence rectangle (19,15),(19,-1),(-15,-1),(-15,15) and horizontal transverse axis.      Log On


   

Question 1135422: write the equation of the hyperbola in standard form given the corners of refrence rectangle (19,15),(19,-1),(-15,-1),(-15,15) and horizontal transverse axis.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The center of the hyperbola is the center of the reference rectangle -- (2,7).

Half the length of the transverse (horizontal) axis is 17; half the length of the conjugate (vertical) axis is 8.

So the equation is

%28x-2%29%5E2%2F17%5E2-%28y-7%29%5E2%2F8%5E2+=+1