SOLUTION: Find an equation of the circle whose diameter has endpoints (-3,2) and (2,2)

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Question 1134506: Find an equation of the circle whose diameter has endpoints (-3,2) and (2,2)
Found 2 solutions by mathsolverplus, ikleyn:
Answer by mathsolverplus(88) About Me  (Show Source):
You can put this solution on YOUR website!
d=sqrt%28%282-%282%29%29%5E2%2B%282-%28-3%29%29%5E2%29
d=sqrt%2825%29
d=5
If diameter = 5, radius = 2.5 because radius is half of diameter.
Now, we need to find the center of the circle, which is midpoint between the two given points.
Midpoint = ((-3+2)/2, (2+2)/2)
= (-1/2, 2)
The equation of a circle:
%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 (h,k) is the center and r = 5/2
We found center to be (-1/2,2) and radius = 5/2:
Solution: %28x%2B%281%2F2%29%29%5E2%2B%28y-2%29%5E2=25%2F4


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Answer by ikleyn(52797) About Me  (Show Source):
You can put this solution on YOUR website!
.
The center has x-coordinate  %28-3%2B2%29%2F2 = -0.5  and y-coordinate  2.


The diameter is sqrt%282-%28-3%29%5E2+%2B+%282-2%29%5E2%29 = sqrt%285%5E2%29 = 5.


The radius is  5%2F2 = 2.5.


So the standard equation of the circle is 


    %28x%2B0.5%29%5E2 + %28y-2%29%5E2 = 2.5%5E2.