SOLUTION: Find the locus of a point P(x,y) which moves so that area triangle APB is 5 u^2 where A(-4,0) and B(2,0)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the locus of a point P(x,y) which moves so that area triangle APB is 5 u^2 where A(-4,0) and B(2,0)      Log On


   

Question 1133952: Find the locus of a point P(x,y) which moves so that area triangle APB is 5 u^2 where A(-4,0) and B(2,0)
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The base AB has length 6; the area, one-half base times height, is 5. So the height of the triangle is 5. (1/2 times 6 times 5/3 = 5)

The base is on the horizontal line y=0, so point P can be any point that is 5/3 units vertically from y=0 -- either above or below the base. So the locus of point P is the two horizontal lines y=5/3 and y=-5/3.

Answer by ikleyn(52797) About Me  (Show Source):
You can put this solution on YOUR website!
.
In the post, the variable  u%5E2  is included, but is not defined.


Therefore, the post makes no sense.