SOLUTION: find the locus of P(x,y) if P is equidistant from A (1,4) and the x-axis.

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Question 1132429: find the locus of P(x,y) if P is equidistant from A (1,4) and the x-axis.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let point P(x,y) be on the locus, and A(1,4) given point
distance from x axis is equal to y coordinate,so
so, given AP=y
=> %28AP%29%5E2=y%5E2
=> y%5E2=%28x-1%29%5E2%2B%28y-4%29%5E2
y%5E2=x%5E2-2x%2B1%2By%5E2-8y%2B16
y%5E2-y%5E2%2B8y=x%5E2-2x%2B17
8y=x%5E2-2x%2B17
y=%281%2F8%29x%5E2-%281%2F4%29x%2B17%2F8