SOLUTION: Find the equation of a circle satisfying the given conditions. Center: ​(2​, 4​), radius: sq. rt of 2 The equation of the circle in standard form is___. &#820

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the equation of a circle satisfying the given conditions. Center: ​(2​, 4​), radius: sq. rt of 2 The equation of the circle in standard form is___. &#820      Log On


   

Question 1128655: Find the equation of a circle satisfying the given conditions.
Center: ​(2​, 4​), radius: sq. rt of 2
The equation of the circle in standard form is___. ​(Type an​ equation.)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the equation of a circle satisfying the given conditions.

Center:(2, 4), radius: sqrt%282%29
The center-radius form of the circle equation is in the format:
+%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2+=+r%5E2
+%28x-2%29%5E2+%2B+%28y+-+4%29%5E2+=+%28sqrt%282%29%29%5E2
+%28x-2%29%5E2+%2B+%28y+-4%29%5E2+=+2
The equation of the circle in standard form is_+%28x-2%29%5E2+%2B+%28y+-+4%29%5E2+=+2__.