SOLUTION: The circle given by x^2+y^2-6y-12=0 can be written in standard form like this: x^2+(y-k)^2=21. What is the value of k in this solution?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: The circle given by x^2+y^2-6y-12=0 can be written in standard form like this: x^2+(y-k)^2=21. What is the value of k in this solution?      Log On


   



Question 1128402: The circle given by x^2+y^2-6y-12=0 can be written in standard form like this: x^2+(y-k)^2=21. What is the value of k in this solution?
Answer by josgarithmetic(39620) About Me  (Show Source):