.
It is NOT AN ELLIPSE ! It is a hyperbola ! !
Fix an error in your condition ! ! !
9x² - 3y² - 36x - 6y + 12 = 0.
Complete the squares for x-terms and y-terms separately, step by step
(9x^2 - 36x) - (3y^2 + 6y) = -12
9*(x^2 - 4x) - 3*(y^2 + 2y) = -12
9*(x^2 -4x + 4) - 3*(y^2 + 2y + 1) = -12 + 9*4 - 3
9*(x-2)^2 - 3*(y+1)^2 = 21.
Divide both sides by 21
-
= 1, or equivalently
-
= 1,
-
= 1. (Equation of a hyperbola)
Thus a=
, b=
, and c =
=
=
=
.