SOLUTION: Solve;x^2+5x-6=0 using graphical method. Solve; x^2-3x-8=0 by factorization. Solve; 4c+3d=1 and 5c+4d=2 using substitution method

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Solve;x^2+5x-6=0 using graphical method. Solve; x^2-3x-8=0 by factorization. Solve; 4c+3d=1 and 5c+4d=2 using substitution method      Log On


   

Question 1123970: Solve;x^2+5x-6=0 using graphical method.
Solve; x^2-3x-8=0 by factorization.
Solve; 4c+3d=1 and 5c+4d=2 using substitution method
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
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Solve;x^2+5x-6=0 using graphical method.
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You could try factorizing first.
%28x-1%29%28x%2B6%29=0
zeros are 1 and -6.
Parabola crosses x axis at those two coordinates for x.

graph%28300%2C300%2C-8%2C8%2C-8%2C8%2Cx%5E2%2B5x-6%29