SOLUTION: ok. i have gotten to x=3(-9 +/-(square root of 71) /all over 10) +3 i need to figure out what x can be. thank you

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: ok. i have gotten to x=3(-9 +/-(square root of 71) /all over 10) +3 i need to figure out what x can be. thank you      Log On


   

Question 111009: ok. i have gotten to x=3(-9 +/-(square root of 71) /all over 10) +3
i need to figure out what x can be. thank you
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
i have gotten to x=3(-9 +/-(square root of 71) /all over 10) +3
i need to figure out what x can be
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I can't imagine how you came up with this but.......
x = 3[-9 +- sqrt(71)/10] + 3
x = 3[-9+(1/10)sqrt(71)] +3
Or
x = 3[-9-(1/10)sqrt(71)] +3
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Cheers,
Stan H.