SOLUTION: Please help me with this problem. I got 4(x-2)^2-9(y+1)^2=0 Is this Hyperbola? Can I write this in transformational form? I am not sure how I can put this into standard hyperbol

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Please help me with this problem. I got 4(x-2)^2-9(y+1)^2=0 Is this Hyperbola? Can I write this in transformational form? I am not sure how I can put this into standard hyperbol      Log On


   

Question 1108997: Please help me with this problem.
I got 4(x-2)^2-9(y+1)^2=0 Is this Hyperbola?
Can I write this in transformational form? I am not sure how I can put this into standard hyperbola equation (x/a)^2-(y/b)^2=1.
Thank you.
Answer by ikleyn(52802) About Me  (Show Source):
You can put this solution on YOUR website!
.
The equation in the post


    4%28x-2%29%5E2 - 9%28y%2B1%29%5E2 = 0


IS NOT a hyperbola equation.


This equation describes two intersecting straight lines.


You CAN NOT transform it into the standard hyperbola equation form.

--------------
On standard hyperbola equation form and related transformations see the lessons
    - Standard equation of a hyperbola
    - Identify elements of hyperbola given by its standard equation
    - Find the standard equation of a hyperbola given by its elements

    - General equation of a hyperbola
    - Transform general equation of a hyperbola to the standard form by completing the square
    - Identify elements of a hyperbola given by its general equation

    - OVERVIEW of lessons on hyperbolas


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic
"Conic sections: Hyperbolas. Definition, major elements and properties. Solved problems".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.