SOLUTION: Find the equation of the parabola described: Focus at (0,2); vertex at (0,0). Graph the parabola and the directrix.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the equation of the parabola described: Focus at (0,2); vertex at (0,0). Graph the parabola and the directrix.      Log On


   

Question 109927: Find the equation of the parabola described: Focus at (0,2); vertex at (0,0). Graph the parabola and the directrix.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The focus lies 2 units above+the+vertex, so:
the parabola is vertical and p+=+2.
The+endpoints of the focal chord lie | 2+p | to the left and right of the focus
at points (+-+4, 2 ) and ( 4, 2 ).
x%5E2+=+8+y y+=+%281%2F8%29x%5E2+

Solved by pluggable solver: PLOT any graph
Graphing function %281%2F8%29x%5E2:

graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F8%29x%5E2+%29