SOLUTION: An archway that is above a highway is in the shape of a semi-ellipse 60 ft wide and 25 ft high. How high is the archway 10 ft away from the center ?

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Question 1092228: An archway that is above a highway is in the shape of a semi-ellipse 60 ft wide and 25 ft high. How high is the archway 10 ft away from the center ?
Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
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The ellipse has the major axis of 60 ft long; hence, the major semi-axis is 30 ft long.

The minor semi-axis is 25 ft long.


Hence, the ellipse canonical equation is 

x%5E2%2F30%5E2 + y%5E2%2F25%5E2 = 1.


From it,  y = 25%2Asqrt%281-x%5E2%2F30%5E2%29.


Therefore, to find the answer, substitute x= 10 to the formula and calculate


y = 25%2Asqrt%281-10%5E2%2F30%5E2%29 = 25%2Asqrt%281+-+1%2F9%29 = 25%2Asqrt%288%2F9%29 = 23.57 ft.


Solved.


See the lesson
    - Ellipse definition, canonical equation, characteristic points and elements
in this site.