SOLUTION: Parabola The antenna of a radio telescope is paraboloid measuring 81 feet across with depth of 16 feet. Determine, to the nearest tenth of a foot, the distance from the vertex t

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Parabola The antenna of a radio telescope is paraboloid measuring 81 feet across with depth of 16 feet. Determine, to the nearest tenth of a foot, the distance from the vertex t      Log On


   



Question 1091793: Parabola
The antenna of a radio telescope is paraboloid measuring 81 feet across with depth of 16 feet. Determine, to the nearest tenth of a foot, the distance from the vertex to the focus of this antenna.
Please help. Thank you

Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
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The antenna of a radio telescope is paraboloid measuring 81 feet across with depth of 16 feet.
Determine, to the nearest tenth of a foot, the distance from the vertex to the focus of this antenna.
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If you read the lesson

    - Parabola definition, canonical equation, characteristic points and elements 

in this site, you will learn that if you write the canonical equation of a parabola in the form

y = %281%2F%282%2Ap%29%29%2Ax%5E2,     (1)


then the distance from the parabola's vertex (0,0) to the parabola's focus  (focal distance) is  p%2F2.


So, our nearest task is to present the equation of our parabola in the form (1).

For it, substitute y = 16 (depth in feet)  and  x = 81%2F2  into equation (1). You will get then

16 = %281%2F%282%2Ap%29%29%2A%2881%2F2%29%5E2,   or  2p = %28%2881%2F2%29%5E2%29%2F16 = 81%5E2%2F%284%2A16%29.


Then  p = 81%5E2%2F%288%2A16%29 = 51.258.


Thus the focal distance is  p%2F2 = 51.258%2F2 = 25.629 ft.

Answer. The focal distance is 25.629 ft.


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The referred lesson is the part of this online textbook under the topic
"Conic sections: Parabolas. Definition, major elements and properties. Solved problems".


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