SOLUTION: Please help me solve this hyperbola equation with vertices(5,-3) and (-1,-3) and afocus at (7,-3)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Please help me solve this hyperbola equation with vertices(5,-3) and (-1,-3) and afocus at (7,-3)      Log On


   



Question 1087740: Please help me solve this hyperbola equation with vertices(5,-3) and (-1,-3) and afocus at (7,-3)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
hyperbola equation with vertices (5,-3) and (-1,-3) and a focus at (7,-3)
the standard form of the equation is: looking at coordinates of vertices, yu have a horizontal hyperbola
%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1
center: (h, k)
vertices: (h ± a,+k)
foci: (h ± c, k)
The vertices are above and below each other, so the center, foci, and vertices lie on a vertical line paralleling the y-axis
The center is midway between the two vertices, so if vertices at (5,-3) and (-1,-3)
(h,+k)=(%285%2B%28-1%29%29%2F2,%28-3%2B%28-3%29%29%2F2)=(2,-3)
so, h=2
since vertices:
(h ±+a, k) =(5,-3)=>
h ±a=5 and since k=-3 and h=2 we can find a
so,
2%2Ba=5
a=5-2
a=3
since foci:
(h ± c, k)=(7,-3) =>
h+%2Bc=7 and since h=2 we have
c=7-2
c=5
since +c=sqrt%28a%5E2+%2B+b%5E2%29 we can find b
5=sqrt%283%5E2+%2B+b%5E2%29

25=9+%2B+b%5E2
b%5E2=25-9
b%5E2=16
b=4 or b=-4
so, your equation is:
%28x-2%29%5E2%2F3%5E2-%28y%2B3%29%5E2%2F4%5E2=1