SOLUTION: (x+1)^(2)=-4(y-3) principal axis vertex focus directrix endpoints of focal width length of focal width graph thanks. appreciate it. God bless.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: (x+1)^(2)=-4(y-3) principal axis vertex focus directrix endpoints of focal width length of focal width graph thanks. appreciate it. God bless.      Log On


   

Question 1087530: (x+1)^(2)=-4(y-3)
principal axis
vertex
focus
directrix
endpoints of focal width
length of focal width
graph
thanks. appreciate it. God bless.
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B1%29%5E%282%29=-4%28y-3%29

vertex (-1,3)
focus (-1,2)
directrix y=4

%28x%2B1%29%5E2=-4%282-3%29
%28x%2B1%29%5E2=4
x%2B1=0%2B-+2
system%28x=-1-2%2Cor%2Cx=-1%2B2%29
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Endpoints of focal width (-3,2) and (1,2)

-
y-3=%28-1%2F4%29%28x%2B1%29%5E2
y=3-%281%2F4%29%28x%2B1%29%5E2
y=-%281%2F4%29%28x%2B1%29%5E2%2B3
graph%28300%2C300%2C-6%2C4%2C-5%2C5%2C-%281%2F4%29%28x%2B1%29%5E2%2B3%29