SOLUTION: Sketch the graph and identify focus, directrix, vertex, latus rectum and axis of symmetry: y^2 = 40x Thank you very much!

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Sketch the graph and identify focus, directrix, vertex, latus rectum and axis of symmetry: y^2 = 40x Thank you very much!       Log On


   

Question 1087429: Sketch the graph and identify focus, directrix, vertex, latus rectum and axis of symmetry: y^2 = 40x
Thank you very much!
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
y%5E2=40x, also %28y-0%29%5E2=40%28x-0%29


Vertex (0,0)

Parabola has horizontal symmetry axis and focus is to the right of the vertex,
40=4p
p=10
Focus is 10 units to the right of vertex.

FOCUS (0,10)
Directrix x=-10
Symmetry Axis y=0
Vertex (0,0)

graph%28300%2C300%2C-15%2C15%2C-15%2C15%2C-sqrt%2840x%29%2Csqrt%2840x%29%29