SOLUTION: How do I use the elimination method to solve this problem? 3x^2+4y^2=48 2x^2-y^2=-1

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Question 1076997: How do I use the elimination method to solve this problem?
3x^2+4y^2=48
2x^2-y^2=-1
Found 3 solutions by josgarithmetic, Alan3354, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Exactly as you already learned.

Eliminate the x%5E2
Multiply E1 by 2 and multiply E2 by 3; subtract either equation from the other.

Eliminate y%5E2
Just multiply E2 by 4; and add the two equations.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Multiply the 2nd equation by 4 then add the equations.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

How do I use the elimination method to solve this problem?
3x^2+4y^2=48
2x^2-y^2=-1
3x%5E2+%2B+4y%5E2+=+48 ------ eq (i)

2x%5E2+-+y%5E2+=+-1 ------ eq (ii)

Multiply eq (ii) by 4 to get eq (iii)

Add eqs (iii) & (i) to eliminate y%5E2

You'll get 2 values for x. Likewise, you'll get 2 values for y when you substitute each of the 2 x-values into any of the 2 original equations.

That's how simple this is. 

NEVER follow any of the other "respondent's" suggestions, unless you want to CONFUSE yourself and/or wish to spend a lot of time doing a ton of work.