SOLUTION: How are the steps to find the coordinates of the vertex for the parabola defined by the given quadratic function: 2(x-3)^2+1

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Question 1076552: How are the steps to find the coordinates of the vertex for the parabola defined by the given quadratic function:
2(x-3)^2+1
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
2%28x-3%29%5E2%2B1

Vertex occurs in the exact middle of the roots. You can solve for 2%28x-3%29%5E2%2B1=0 and then the average of the roots is the x value for the vertex... but since your function is already given in standard form, the vertex is (3,1).

The vertex for y=a%28x-h%29%5E2%2Bk is the point (h,k).